用因式分解法解下列方程:

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用因式分解法解下列方程。~

1)3X²-12X=-12.
X²-4X+4=0
(x-2)^2=0
x1=x2=2
(2)4X²-144=0
(2x+12)(2x-12)=0
x1=6 ,x2=-6
(3)3X(X-1)=2(X-1)
3x(x-1)-2(x-1)=0
(x-1)(3x-2)=0
x1=1,x2=2/3
(4)(2X-1)²=(3-x)²
(2X-1)²-(3-x)²=0
(2x-1+3-x)(2x-1-3+x)=0
(x+2)(3x-4)=0
x1=-2 x2=4/3

1.3y^2-5y=0
y(3y-5)=0
y1=0,y2=3/5
2.4x^2=12x
4x²-12x=0
4(x²-3x)=0
x(x-3)=0
x1=0,x2=3
3.x^2+9=-6x
x²+6x+9=0
(x+3)²=0
x=-3
4.9x^2=(x-1)^2
9x²-(x-1)²=0
[3x+(x-1)][3x-(x-1)]=0
(4x-1)(2x+1)=0
x1=1/4 ,x2=-1/2
(5) (x-2)(2x-3)=6
2x²-3x-4x+6-6=0
2x²-7x=0
x(2x-7)=0
x1=0,x2=2/7
(6) x(x-4)= - 4
x²-4x+4=0
(x-2)²=0
x=2
(7) (2x-1)^2= - 8
x无解
(8) (x-2)^2=2x(x-2)
x²-4x+4-2x²+4x=0
-x²+4=0
x²-4=0
(x+2)(x-2)=0
x1=-2,x2=2
2、解方程 x^2-2√3 x= - 3
x^2-2√3 x +3=0
(x-√3)²=0
x=√3

1.(x+1-根号2)(x+1+根号2)=0; x1= -1+根号2, x2= -1-根号2
2.(x-6)(2x+3)=0 ; x1=6, x2= -3/2

(x+1-根号2)(x+1+根号2)=0
(x-6)(2x+3)=0

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